24x^2+116x+80=0

Solution for 24x^2+116x+80=0 equation:

24x^2+116x+80=0

a = 24; b = 116; c = +80;
Δ = b2-4ac
Δ = 1162-4·24·80
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(116)-76}{2*24}=\frac{-192}{48}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(116)+76}{2*24}=\frac{-40}{48}
=-5/6
$